引入一个队列即可。

'''
从上往下打印出二叉树的每个节点,同层节点从左至右打印。
'''

'''
相当于按层遍历, 中间需要队列做转存
'''

# -*- coding:utf-8 -*-
class TreeNode:
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None
class Solution:
    # 返回从上到下每个节点值列表,例:[1,2,3]
    def PrintFromTopToBottom(self, root):
        queue = []
        if not root:
            return []

        result = []
        queue.append(root)
        while len(queue) > 0:
            currentRoot = queue.pop(0)
            result.append(currentRoot.val)
            if currentRoot.left:
                queue.append(currentRoot.left)
            if currentRoot.right:
                queue.append(currentRoot.right)
        return result

pNode1 = TreeNode(8)
pNode2 = TreeNode(6)
pNode3 = TreeNode(10)
pNode4 = TreeNode(5)
pNode5 = TreeNode(7)
pNode6 = TreeNode(9)
pNode7 = TreeNode(11)

pNode1.left = pNode2
pNode1.right = pNode3
pNode2.left = pNode4
pNode2.right = pNode5
pNode3.left = pNode6
pNode3.right = pNode7

S = Solution()
print(S.PrintFromTopToBottom(pNode1))